Oracle 1z0-061日本語 : Oracle Database 12c: SQL Fundamentals (1z0-061日本語版)

1z0-061日本語 real exams

Exam Code: 1z0-061-JPN

Exam Name: Oracle Database 12c: SQL Fundamentals (1z0-061日本語版)

Updated: Sep 22, 2026

Q & A: 340 Questions and Answers

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Oracle 1z0-061日本語 Exam Overview:

Certification Vendor:Oracle
Exam Name:Oracle Database 12c: SQL Fundamentals
Exam Number:1Z0-061
Exam Format:Scenario-based questions, Multiple-choice
Exam Price:USD 125–245 / JPY 13,600
Related Certifications:Oracle Database SQL Certified Associate
Oracle Database 12c Administrator Certified Associate
Certificate Validity Period:No expiration (valid indefinitely)
Real Exam Qty:75
Available Languages:Japanese, English
Exam Duration:120 minutes
Passing Score:65%
Recommended Training:Oracle Learning Library
Oracle Database 12c: Introduction to SQL
Exam Registration:Pearson VUE Registration
Oracle Education
Sample Questions:Free Download Oracle 1z0-061日本語 prep pass
Exam Way:In-person at Pearson VUE test centers or online proctored exam (region-dependent)
Pre Condition:No required prerequisites; basic knowledge of relational databases and SQL recommended
Official Syllabus URL:https://education.oracle.com/oracle-database-12c-sql-fundamentals/pexam_1Z0-061

Oracle 1z0-061日本語 Exam Syllabus Topics:

SectionWeightObjectives
Topic 1: Displaying Data from Multiple Tables10%- Using different types of joins
- Joining tables using SQL:1999 syntax
Topic 2: Using Subqueries8%- Single-row and multi-row subqueries
- Nesting subqueries
Topic 3: Retrieving Data Using the SQL SELECT Statement15%- Executing basic SELECT queries
- Capabilities of SELECT statements
Topic 4: Aggregated Data with Group Functions10%- AVG, SUM, MAX, MIN, COUNT functions
- Filtering groups with HAVING clause
- Grouping results with GROUP BY
Topic 5: Restricting and Sorting Data15%- Using substitution variables
- Sorting results with ORDER BY
- Limiting rows with WHERE clause
Topic 6: Conversion Functions and Conditional Expressions15%- TO_CHAR, TO_NUMBER, TO_DATE conversions
- CASE, DECODE and conditional logic
Topic 7: Managing Data and Schema Objects7%- Basic DDL: CREATE, ALTER, DROP tables
- DML operations: INSERT, UPDATE, DELETE
- Constraints and schema objects
Topic 8: Using Single-Row Functions20%- Manipulating data values
- Character, number, and date functions

Oracle Database 12c: SQL Fundamentals (1z0-061日本語版) Details Every Buyer Should Read

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About 75 questions in 120 minutes minutes. The Prep4pass software version recreates that scene for unlimited rehearsal, and 340 practice questions for the 1z0-061日本語 exam give you plenty of material to run through it.
The official Oracle Database 12c: SQL Fundamentals (1z0-061日本語版) outline weights its topics like this:
  • Restricting and Sorting Data (15%)
  • Retrieving Data Using the SQL SELECT Statement (15%)
  • Using Single-Row Functions (20%)
Spend the bulk of your hours where the points are, and test each domain with the Prep4pass bank as you finish it.
Because time is the one resource you cannot buy back. An early start lets the 1z0-061日本語 material breathe: a first pass through the Oracle Database 12c: SQL Fundamentals (1z0-061日本語版) bank to map the territory, timed simulations to build pace, and a calm final review instead of a desperate cram. It also means every update released during your preparation reaches you automatically, so you always study the latest version. Earlier really is easier.
No required prerequisites; basic knowledge of relational databases and SQL recommended
The passing mark is 65% and the exam fee is USD 125–245 / JPY 13,600. Since retakes charge that fee again, thorough preparation with verified Prep4pass material is money well spent.
Because the safety nets are real: 340 practice questions for the 1z0-061日本語 exam with verified answers, a free demo before you pay, a one-time exchange if you pick the wrong exam code, updates sent to you the moment they release for 365 days, support that answers within about three hours even on official holidays, and a conditional refund policy behind it all. Preparation stays calm when the logistics take care of themselves.
Oracle Database 12c: Introduction to SQL Oracle Learning Library Pair structured official training with the verified Prep4pass bank, and you cover both the theory and the exam-hall rehearsal.

Oracle Database 12c: SQL Fundamentals (1z0-061日本語版) Sample Questions:

Question #1

リレーショナルデータベース(RDB)モデルとオブジェクト指向データベース(OODB)モデルの主な違いは何ですか?

  • A. OODBにはデータ構造定義を含むメソッドが組み込まれていますが、RDBではこれが許可されていません。
  • B. RDBは異なるテーブル間の関係の定義を許可しますが、OODBはこれを許可しません。
  • C. RDBはE.F. Coddのルールをサポートしていますが、OODBはそれらをサポートしていません。
  • D. OODBは同じデータベース内の複数のオブジェクトをサポートしますが、RDBはテーブルのみをサポートします。
Reveal Solution  Discussion  0

Correct Answer: A  🗳️

Question #2

サブクエリに関して正しい3つのステートメントはどれですか。 (3つ選択してください。)

  • A. サブクエリにGROUP BY句とORDER BY句を含めることができます
  • B. メインクエリとサブクエリは同じテーブルからデータを取得する必要があります
  • C. サブクエリにはORDER BYを含めることができますが、GROUP BY句を含めることはできません
  • D. メインクエリとサブクエリは異なるテーブルからデータを取得できます
  • E. メインクエリとサブクエリの間で比較できる列または式は1つだけです
  • F. メインクエリとサブクエリの間で複数の列または式を比較できます
Reveal Solution  Discussion  0

Correct Answer: A,D,F  🗳️

Question #3

展示を表示し、CUSTOMERSテーブルの説明を調べます。

CUST_ID 2360の顧客のCUST_INCOME_LEVELおよびCUST_CREDIT_LIMIT列を更新します。CUST_INCOME_LEVELの値は、CUST_ID 2560の顧客と同じ値にし、CUST_CREDIT_LIMITは、CUST_CREDIT_LIMITと同じ値にします。 CUST_IDの顧客
2566。
どのUPDATEステートメントがタスクを実行しますか?

  • A. UPDATE customersSET (cust_income_level, cust_credit_limit)
    (SELECTcust_income_level, cust_credit_limitFROM customersWHERE cust_id=2560 OR cust_id=2566)WHERE cust_id=2360;
  • B. UPDATE customersSET (cust_income_level, cust_credit_limit)
    (SELECTcust_income_level, cust_credit_limitFROM customersWHERE cust_id IN(2560,
    2 566)WHERE cust_id=2360;
  • C. UPDATE customersSET (cust_income_level, cust_credit_limit)
    (SELECTcust_income_level, cust_credit_limitFROM customersWHERE cust_id=2560 AND cust_id=2566)WHERE cust_id=2360;
  • D. UPDATE customersSET cust_income_level = (SELECT cust_income_levelFROM customersWHERE cust_id = 2560),cust_credit_limit = (SELECT cust_credit_limitFROM customersWHERE cust_id = 2566)WHERE cust_id=2360;
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

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Question #4

展示を表示し、製品、コンポーネント、およびPDT_COMPテーブルの構造を調べます。
製品表では、PDTNOが主キーです。
コンポーネントテーブルでは、COMPNOが主キーです。
PDT_COMPテーブルでは、<PDTNO、COMPNO)は主キー、PDTNOは製品テーブルのPDTNOを参照する外部キー、COMPNOはコンポーネントテーブルのCOMPNOを参照する外部キーです。
コンポーネント名と製品名が存在する場合、製品名とそれに対応するコンポーネント名をリストするレポートを生成します。
次のクエリを評価します。
SQL> SELECT pdtno、pdtname、compno、compname
FROM製品_____________ pdt_comp
USING(pdtno)____________コンポーネントUSING(compno)
WHERE compnameがNULLではありません。
上記のクエリの空白で使用されている結合のどの組み合わせが正しい出力を提供しますか?

  • A. FULL OUTER JOIN;完全外部結合
  • B. 参加;参加する
  • C. 左外部結合。右外部結合
  • D. 右外部結合。左外部結合
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

Question #5

展示を表示し、CUSTOMERSテーブルの構造を調べます。

CUSTOMERSテーブルのCUST_LAST_NAME列には、値「アンダーソン」と「オーソン」が含まれています。
次のクエリを発行します。

結果はどうなりますか?

  • A. 指定されたLOWER関数が無効であるためエラー
  • B. 指定されたREPLACE関数が無効なためエラー
  • C. 指定されたTRIM関数が無効なためエラー
  • D. 「オーダー」と「オーストラリア」
Reveal Solution  Discussion  0

Correct Answer: C  🗳️

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