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NEW QUESTION # 19
Which two statements about building an app are true? (Choose 2.)
- A. You can run an app on your phone and get debug information in Xcode.
- B. You can preview a View in the Canvas without running your app.
- C. Your phone must always be physically attached to your Mac to run your apps from Xcode on it.
- D. You need a paid Apple Developer account in order to run your app on your phone.
- E. You can run your app in the simulator with Generic iOS Device chosen.
Answer: A,B
Explanation:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to Xcode Developer Tools , especially the objectives about using the Xcode interface, building and running an app, and debugging. A is true because Xcode supports SwiftUI previews in the canvas, allowing you to see a view's interface directly in Xcode without fully launching the entire app in the normal run workflow. Apple's documentation states that Xcode can display a preview of a custom SwiftUI view in the preview canvas and keep it updated as you make code changes.
D is also true because when you run an app from Xcode on a device, Xcode opens a debugging session in the debug area. Apple explicitly documents that after a successful build, Xcode runs the app and opens a debugging session, which means you can view debug information while the app is running on the phone.
The other options are false. B is false because a phone does not have to be physically attached at all times; modern Xcode workflows support device pairing and wireless development after setup. C is false because Generic iOS Device is not an actual simulator run target for launching the app like a specific simulator device. E is false because you do not need a paid Apple Developer Program membership merely to run an app on your own device for development; Apple provides support for development testing on devices with the required setup such as pairing and Developer Mode.
NEW QUESTION # 20
Review the code snippet.
Move each item from the list on the left to the correct code segment on the right. You may use each item only once.
Note: You will receive partial credit for each correct response.
Answer:
Explanation:
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, properties, methods, and initializers .
A computed property does not store a value directly. Instead, it returns a value calculated from other data.
That is why description is a computed property: it returns a string based on content.
A memberwise initializer is automatically provided by Swift for structs when their stored properties are initialized through parameters. So Document(content: " Greetings! " ) is using the struct's memberwise initializer.
A type property belongs to the type itself rather than to an instance. In Swift, static var docCount = 0 is a type property because it is declared with static.
An instance method is a function that belongs to an instance of the struct or class. The display() method uses the instance's content, so it is an instance method.
A type method is a method declared with static and belongs to the type itself. So static func increment() is a type method because it changes the shared type property docCount.
NEW QUESTION # 21
Complete the code that will add the BlueView to the NavigationStack and present the RedView modally.
|Complete the code by typing in the boxes.
Answer:
Explanation:
NavigationLink, .sheet
Explanation:
This question falls under View Building with SwiftUI , specifically the domain covering multi-view apps with navigation stacks, links, and sheets . The first blank must be NavigationLink because SwiftUI uses a navigation link inside a NavigationStack to push or present a destination view as part of the navigation hierarchy. Apple's documentation states that people tap or click a NavigationLink to present a view inside a NavigationStack or NavigationSplitView. That matches the first code section, where tapping " Show Blue View " should navigate to BlueView().
The second blank must be .sheet because the code uses isPresented: $showRedView, which is the standard SwiftUI sheet modifier for modal presentation controlled by a Boolean binding. Apple documents sheet (isPresented:onDismiss:content:) as the modifier to use when you want to present a modal view when a Boolean becomes true. Since the button toggles showRedView, SwiftUI presents RedView() modally as a sheet.
So the completed structure is effectively:
NavigationLink( " Show Blue View " ) {
BlueView()
}
sheet(isPresented: $showRedView) {
RedView()
}
This directly aligns with SwiftUI navigation and modal presentation patterns in the App Development with Swift objective domains.
NEW QUESTION # 22
Review the code snippet.
What is the value of answer after you run the code?
Answer:
Explanation:
4
Explanation:
This question belongs to Swift Programming Language , specifically the domains covering control flow , loops , and range operators .
The code starts with:
var count = 0
var answer = 0
So both variables begin with the value 0.
In the first loop:
for index in 1...5 {
count = index
}
the closed range 1...5 includes 1, 2, 3, 4, and 5 . During each iteration, count is updated to the current value of index. After the loop finishes, the final value assigned to count is 5 .
Then the second loop runs:
for index in 1.. < count {
answer = index
}
Here, the half-open range 1.. < count means values starting at 1 up to, but not including , count. Since count is 5, this loop runs with index equal to 1, 2, 3, and 4 . Each time through the loop, answer is updated to the current index. After the last iteration, answer becomes 4 .
So the final value of answer is 4 . This question tests understanding of the difference between the closed range operator ... and the half-open range operator .. < , which is a key Swift control-flow concept.
NEW QUESTION # 23
Review the code snippet.
What is the output from each print statement?
Answer:
Explanation:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
NEW QUESTION # 24
Review the code snippet and then predict the output.
- A. Total count: 10
- B. Total count: 9
- C. Total count: 20
- D. Total count: 11
Answer: A
Explanation:
This question belongs to Swift Programming Language , especially the domains covering control flow , loops , logical operators , and guard . The loop runs through 0.. < max, and since max = 101, the values of num are 0 through 100. Inside the loop, the guard statement keeps only values that satisfy both conditions:
* num % 5 == 0 # the number must be divisible by 5
* num % 2 != 0 # the number must be odd
So the code counts numbers from 0 to 100 that are odd multiples of 5 . Those values are:
5, 15, 25, 35, 45, 55, 65, 75, 85, 95
That gives a total of 10 numbers. Therefore count becomes 10, and the printed output is:
Total count: 10
The key Swift concept here is that guard ... else { continue } skips any loop iteration that does not meet the required condition. Only matching values reach count += 1. This is a standard use of guard for early exit and of the remainder operator % for divisibility checks. Therefore, the correct answer is B .
NEW QUESTION # 25
Refer to this image to complete the code.
Note: You will receive partial credit for each correct answer
Answer:
Explanation:
Explanation:
This question belongs to View Building with SwiftUI , especially the objectives for using List views to iterate through collections and structuring views with standard SwiftUI containers. The screenshot shows two grouped sets of rows: one headed MY FRIENDS and one headed MY PETS . In SwiftUI, the correct container for a scrollable table-style presentation of rows is List, and the correct way to divide that list into labeled groups is Section. Apple documents List as a container that presents data in a single-column row- based layout, and Section as a way to organize list content into grouped areas with headers and optional footers. That is exactly the structure shown in the image. ( developer.apple.com , developer.apple.com ) The ForEach(names, id: \.self) and ForEach(pets, id: \.self) lines are already iterating through the arrays, so each ForEach should be wrapped inside a Section. The section labels such as " My Friends " and " My Pets
" are provided with the header: label. So the intended code structure is:
List {
Section {
ForEach(names, id: \.self) { name in Text(name) }
} header: {
Text( " My Friends " )
}
Section {
ForEach(pets, id: \.self) { pet in Text(pet) }
} header: {
Text( " My Pets " )
}
}
This matches the UI shown in the image and aligns directly with SwiftUI list and section composition patterns in App Development with Swift.
NEW QUESTION # 26
Which code correctly creates a size 300 rectangular Image View with rounded corners that displays the entire image, regardless of size?
- A.
- B.
- C.
- D.
Answer: B
Explanation:
This question belongs to View Building with SwiftUI , specifically the objective on positioning and laying out a single SwiftUI view with standard views and modifiers.
The correct answer is D because it uses the right combination of SwiftUI image modifiers for all three requirements:
* the image is made resizable with .resizable()
* it is given rounded corners with .clipShape(RoundedRectangle(cornerRadius: 50))
* it displays the entire image with .aspectRatio(contentMode: .fit)
* it is sized with .frame(width: 300)
The key part is .aspectRatio(contentMode: .fit) . In SwiftUI, .fit scales the image so the whole image remains visible inside the available frame. That matches the requirement "displays the entire image, regardless of size." By contrast, .fill may crop part of the image, so options using .fill do not satisfy the requirement.
Why the others are wrong:
* Option A uses .fill, so the full image may not remain visible.
* Option B uses invalid modifiers such as .sizablc() and .size(width: 300), and also uses Rectangle (cornerRadius: 50), which is not the correct rounded-rectangle shape syntax.
* Option C also uses invalid syntax and .fill, which can crop the image.
* Option D uses valid SwiftUI syntax and the correct content mode.
So the correct choice is D , because it is the only option that correctly creates a 300-width image with rounded corners while ensuring the entire image is shown.
NEW QUESTION # 27
Drag the views on the left to the correct locations m the code on the fight to match the shown canvas.
You may use each View once, more than once, or not at all.
Answer:
Explanation:
Explanation:
* RedCircleView()
* GreenTriangleView()
* BlueSquareView()
* BlueSquareView()
* GreenTriangleView()
This question belongs to View Building with SwiftUI , specifically arranging views with HStack , VStack , and ZStack . In SwiftUI, an HStack lays views out horizontally, a VStack lays them out vertically, and a ZStack overlays views front-to-back. Apple's stack layout guidance describes these three containers exactly this way.
To match the canvas, the main HStack must show three items from left to right: a red circle , a green triangle
, and then a right-side vertical group. That means the first two blanks inside HStack are RedCircleView() and GreenTriangleView(). On the right side, the VStack shows a blue square on top, so the next blank is BlueSquareView(). Under that, the lower-right shape is made by layering a green triangle on top of a blue square , which means the ZStack must contain BlueSquareView() first as the background and GreenTriangleView() second as the foreground. SwiftUI's documentation notes that ZStack aligns and overlays its children in depth order, which is why the square goes before the triangle.
So the correct placement order is:
HStack {
RedCircleView()
GreenTriangleView()
VStack {
BlueSquareView()
ZStack {
BlueSquareView()
GreenTriangleView()
}
}
}
That arrangement reproduces the exact layout shown in the canvas.
NEW QUESTION # 28
Review the code snippet.
Which statement completes the code snippet so that:
* The lastReleaseDate remains the same when nextApplePhone.releaseDate is nil.
* The lastReleaseDate updates to the nextApplePhone.releaseDate when nextApplePhone.releaseDate is NOT nil.
- A. lastReleaseDate : nextApplePhone.releaseDate
- B. lastReleaseDate : nextApplcPhone.rcleaseDate!
- C. nextApplePhone.releaseDate : lastReleaseDate
- D. nextApplePhone.releaseDate! : lastReleaseDate
Answer: D
Explanation:
This question is from Swift Programming Language , especially the domains for Optional types , safe and unsafe unwrapping , and control flow . The code uses the ternary conditional operator :
nextApplePhone.releaseDate != nil ? _____
In Swift, the ternary operator follows this structure:
condition ? valueIfTrue : valueIfFalse
So if nextApplePhone.releaseDate != nil is true, the expression must return the new release date. If it is false, it must keep lastReleaseDate unchanged. That means the missing part must be:
nextApplePhone.releaseDate! : lastReleaseDate
which is option D .
This works because nextApplePhone.releaseDate is declared as String?, so it is an optional. Once the condition confirms it is not nil, the code force-unwraps it with ! to access the underlying String value. If the optional is nil, the expression returns lastReleaseDate instead. Apple's Swift documentation describes the ternary conditional operator as a shortcut for choosing one of two expressions based on a condition, and it explains that force unwrapping with ! accesses an optional's wrapped value when you know it is not nil.
The other options are incorrect because they reverse the true/false logic, omit the needed unwrap, or contain invalid identifiers. Therefore, the correct completion is D .
NEW QUESTION # 29
Review the code snippet.
The " faces " dictionary contains emojis and their descriptions.
Which code will create an array named " emo)is " that will copy all the emojis from the " faces " dictionary?
- A. let emojis - List(faces.koys())
- B. let emojis List(faces.values())
- C. let emojis - Array(faces.values)
- D. let emojis = Array(faces.keys)
Answer: D
Explanation:
This question belongs to Swift Programming Language , specifically the objective on managing data using collection types , including dictionaries and arrays . In the dictionary shown, the emojis are the keys and the text descriptions are the values . Swift provides a keys property on dictionaries that returns a collection containing all dictionary keys. To convert that keys collection into an array, you use the Array(...) initializer.
Therefore, the correct code is let emojis = Array(faces.keys). Apple documents both the Dictionary.keys property and the Array type used to store a sequence of values of the same type.
Option B is incorrect because faces.values would return the descriptions like " grinning " , " thinking " , and " happy " , not the emoji keys. Options A and C are incorrect because List is a SwiftUI view type, not the correct collection type for creating an array from dictionary contents. Also, the dictionary interface uses properties like .keys and .values, not method calls like .keys() or .values(). Apple's dictionary documentation makes clear that keys is a property returning a collection of the dictionary's keys.
NEW QUESTION # 30
Select the location to set this app to run on an iPhone 14 in the simulator.
Answer:
Explanation:
Explanation:
This question belongs to Xcode Developer Tools , specifically the domain for building and running an app on the iOS simulator . In Xcode, the place where you choose whether the app runs on a simulator or a connected device is the run destination / scheme destination selector in the toolbar. This control appears near the top center of the Xcode window and displays the current destination, such as a simulator model or device target. To run the app on iPhone 14 , you click that selector and choose iPhone 14 from the available simulator list. Apple's Xcode documentation describes choosing a run destination before building and running the app in Simulator or on a device.
So, for the hotspot, the correct place is the device/simulator dropdown in the top toolbar , not the preview canvas controls, not the project navigator, and not the code editor. That selector determines where the app launches when you press Run.
NEW QUESTION # 31
Given the function, which two function calls are valid? (Choose 2.)
- A. let sum = rightSum(100, num2: SO, and: 20)
- B. let sum - rightSum(100, by: 30, and: 20)
- C. let Sun - rightSum(numl: 100, by: SO, and: SO)
- D. let sum r\ ght5um(100, by: 50)
- E. let sun = rightSum(numl: 100, num2: 50)
Answer: B,D
Explanation:
This question belongs to Swift Programming Language , specifically the domain on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func rightSum(_ num1: Int, by num2: Int, and num3: Int = 25) - > Int {
return num1 + num2 + num3
}
This means:
* the first parameter uses _, so it has no external label
* the second parameter must use the external label by
* the third parameter must use the external label and
* the third parameter also has a default value of 25, so it may be omitted Now evaluate each option:
* A is invalid because it uses num2: instead of the required external label by:
* B is valid because it correctly uses no label for the first argument, then by: and and:
* C is invalid because the first parameter cannot be called with num1: since the external label is omitted with _
* D is valid because it correctly passes the first argument unlabeled and the second with by:, while omitting the third argument so Swift uses the default value 25
* E is invalid because it uses num1: and num2: instead of the required calling syntax So the two correct function calls are B and D .
NEW QUESTION # 32
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
- A. schedule(who name: " Jane Doe " , from starting: " 9:30am " , to ending: " 10:30am " )
- B. schedule(who: " Jane Doe " , from: " 9:30am " , to: " 10:30am " , place: " Office " )
- C. E. schedule(who: " Jane Doe " , from: " 9:30am " , to: " 10:30am " )
- D. schedule(who: " Jane Doe " , from: " 9:30am " , to: " 10:30am " , " Office " )
- E. D. schedule(name: " Jane Doe " , starting: " 9:30am " , ending: " 10:30am " , place: " Office " )
Answer: A,C
Explanation:
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
NEW QUESTION # 33
Review the code.
var capitalCities = [ " USA " : " Washington D.C. " , " Spain " : " Madrid " , " Peru " : " Lima " ] Which two statements add the capital city of " Italy " to the dictionary? (Choose 2.)
- A. capitalCities[ " Rome " ] = " Italy "
- B. capitalCities = capitalCities + [ " Italy " : " Rome " ]
- C. capitalCities.updateValue( " Rome " , forKey: " Italy " )
- D. capitalCities.append([ " Italy " : " Rome " ])
- E. capitalCities[ " Italy " ] = " Rome "
Answer: C,E
NEW QUESTION # 34
Match the Swift Properly Wrapper names to the correct descriptions.
Answer:
Explanation:
Explanation:
* @AppStorage # This property wrapper reads and writes values from UserDefaults.
* @Environment # This property wrapper allows you to access data from the system, such as knowing the size class of the device, or dismissing a view.
* @Binding # When a variable is declared with this property wrapper, changes to its value will be returned to the calling view.
* @State # When a variable is declared with this property wrapper, it is used to store small amounts of data local to the view whose value may affect the appearance of the view.
This question belongs to View Building with SwiftUI , specifically the objective about using @State,
@Binding, @Environment, and related wrappers to share and manage data between views. @AppStorage is the wrapper that connects a SwiftUI value to UserDefaults, so it is the correct match for reading and writing persisted user defaults data. Apple documents AppStorage as a property wrapper type that reflects a value from UserDefaults and updates the view when that value changes.
@Environment is used to read values supplied by the system or ancestor views, including interface context like size classes and actions such as dismissing a presented view. Apple's environment documentation explains that SwiftUI automatically sets and updates many environment values for layout and behavior, and App Dev Training materials show environment values being used to dismiss a view.
@Binding represents a two-way connection to a value owned elsewhere, typically in a parent view, so changes made through the binding are reflected back in the source of truth. Apple's SwiftUI data-flow guidance describes bindings as the mechanism used when a child view needs shared control of state with another view.
@State is the correct wrapper for small, local, mutable view state. Apple describes State as the source of truth for data local to a view and recommends it for interface state that affects rendering.
NEW QUESTION # 35
You have created a view which includes some formatted text:
You decide to extract this formatted text into a subview so that you can reuse the formatting for other texts.
You highlight the Text and choose Extract subview.
You refactor ExtractedView to BigGreenTextView.
You add the line let text: String to the extracted view above the body.
You replace " That ' s all folks " with a reference to text
How should you call this extracted View from the original View?
- A. BigGreenTextView(text)
- B. BigGreenTextView(text: " That ' s all folks " )
- C. BigGreenTextView(text: text)
- D. BigGreenTextView( " That ' s all folks " )
Answer: B
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on extracting subviews to simplify the structure of an overlarge View .
When you create a custom SwiftUI view and add a stored property like:
let text: String
that property becomes part of the view's initializer. Since the property name is text, Swift expects you to pass the value using the parameter label text: when creating the view. So the correct call is:
BigGreenTextView(text: " That ' s all folks " )
That makes B the correct answer.
Why the others are wrong:
* A is incorrect because this is not using the expected parameter label.
* C would only be correct if there were already another variable named text in the calling scope and you wanted to pass that variable instead of the literal string shown in the question.
* D is incorrect because it omits the parameter label.
This is a standard SwiftUI pattern: extract reusable formatting into a separate custom View, give it an input property, and then pass the needed value through the initializer using the property label.
NEW QUESTION # 36
......
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